10x^2=27

Solution for 10x^2=27 equation:

10x^2=27

We move all terms to the left:

10x^2-(27)=0

a = 10; b = 0; c = -27;
Δ = b2-4ac
Δ = 02-4·10·(-27)
Δ = 1080
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1080}=\sqrt{36*30}=\sqrt{36}*\sqrt{30}=6\sqrt{30}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{30}}{2*10}=\frac{0-6\sqrt{30}}{20}
=-\frac{6\sqrt{30}}{20}
=-\frac{3\sqrt{30}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{30}}{2*10}=\frac{0+6\sqrt{30}}{20}
=\frac{6\sqrt{30}}{20}
=\frac{3\sqrt{30}}{10}
$